Answer to Question #116848 in General Chemistry for Staci Meo

Question #116848

A gas has a volume of 2.90 cm3 at 226 K. What would the volume be if the temperature were changed to 23.0 °C?

Expert's answer

P*V/T=P₀*V₀/T₀

V=T*P₀*V₀/P*T₀=296*2.90*P₀/226*P=3.798*P₀/P

if VT=const, V=3.8 mL

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