Answer to Question #116191 in General Chemistry for Aiden

Question

A 0.0316 mol simple of nitrogen gas N2 (g) is placed in a 4.00 L container at 315 K

Answer 1

PV = nRT

V = Volume = 4L

n= number of mole =0.0316

R = 0.082

T = 315 K

P = nRT/ V

= (0.0316 × 0.082 × 315)/ 4

= 0.204 atm