Answer to Question #116109 in General Chemistry for Dillon

Question

A scuba divers oxygen tank reads 900 mmHg while on her boat, where the temperature is 27 degrees C. When she dives down to the bottom of the lake and experiences a change is atmospheric pressure the temperature will drop down to –183 degrees C. What will the pressure in her backup tank be at that temperature? (270 mmHg)

Answer 1

We know that for constant volume

$$\frac{P_2}{T_2}=\frac{P_1}{T_1}$$

$P_1= 900\ mm\ Hg\\T_1=300\ K\\T_2=90\ K$

So

$$P_2=\frac{P_1T_2}{T_1}=\frac{900\times90}{300}= 270\ mm\ Hg$$