Answer to Question #115898 in General Chemistry for james

Question

At 463 K, this reaction has a

Answer 1

At 463 K, this reaction has a Kc value of 0.0797.?

X(g) + 2Y(g) <----> 2Z(g)

Calculate Kp at 463K.

$Kp = Kc (RT)^dn$

where dn = change in number of moles.

Kp = 0.0797 (8.314 x 463)^-1 = 2.50 x 10^-5