Question

Calculate the amount of H3O
+
ions in a solution of 0.312 M NaOH

Answer 1

NaOH is strong base hence 100 % dissociation will take place hence

[OH^-]=0.312

$[H^+][OH^-]=10^{-14}$

$[H^+]=\frac{10^{-14}}{0.312}=3.2\times10^{-14}$