2C8H18 + 25O2 = 16CO2 + 18H2O
n(C8H18) = 692g/114g/mol = 6.07g
n(O2) = 1600g/32g/mol = 50 mol
C8H18 is the limiting reactant, O2 is in the excess.
n(CO2) = 6.07*16/2 = 48.56 mol
m(CO2) = 48.56mol*44g/mol = 2136.7 g
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