Answer to Question #115661 in General Chemistry for Cam

Question

Determine the mass of water vapour formed when 1 g of butane is burned

Answer 1

2C₄H₁₀ +13O₂ → 10H₂O + 8CO₂

M(C₄H₁₀) = 58.12 g/mol;

M(H₂O) = 18.015 g/mol;

n=m/M;

n(C₄H₁₀) = (1 g)/(58.12 g/mol) = 0.0172 moles;

Proportion according to the reaction:

2 moles — 10 moles

0.0172 moles — x moles

x = 0.086 moles

m = n×M;

m(H₂O) = 0.086 moles ×18.015 g/mol = 1.55 g

Answer: 1.55 g