Question

How many moles of potassium chloride are there in 1 liter of a 5.5 molar solution?

Answer 1

Solution:

$c(KCl)=\frac{n(KCl)}{V(KCl)} \\n(KCl)=c(KCl)*V(KCl)=5.5*1=5.5(mol)$

Answer:

n(KCl)=5.5 mol