Question

4. A piece of a metal weighing 140 g is initially at 23.0oC and then absorbs 585 cal of heat. The metal has a specific heat of 0.0200 cal/g-1oC-1. What is the final temperature of the metal piece? Assume that all the heat goes to heating the metal.

Answer 1

We know that

$energy =mc_p(T_2-T_1)$

$$585=140\times0.02(T_2-23)\\T_2-23=208.93\\T_2=231.93\ \degree C$$