Question

determine the volume of oxygen needed to react competently with 2.00 L of hydrogen gas to form water vapor at constant temp & pressure

Answer 1

Solution:

 2H₂+O₂=2H₂O

$n(H_{2} )=\frac{V(H_{2} )}{V_{m} }=\frac{2}{22.4} =0.089(mol)$

0.089 mol - x mol

 2H₂+O₂=2H₂O

2 mol - 1 mol

$x=n(O_{2})=\frac{1*0.089}{2}=0.045 (mol)\\ V(O_{2})= n(O_{2})*V_{m}=0.045*22.4=1.0(l)$

Answer:

V(O₂)=1.0 l