Answer to Question #114951 in General Chemistry for Jared

Question #114951
The formula for a hydrate of magnesium sulfate is MgSO4•xH2O. If 1 mol of anhydrous magnesium sulfate is 48.82% of the mass of 1 mol of the hydrate, what is the value of x?
1
Expert's answer
2020-05-10T09:21:45-0400

M(MgSO4) = 120.366 g/mol;

M(H2O) = 18.015 g/mol;


Proportion:

120.366 g (mass of 1 mole of MgSO4) — 48.82 %

Total mass of 1 mole of MgSO4•xH2O — 100 %


M(MgSO4•xH2O) = 246.55 g/mol;

M(MgSO4) + M(xH2O) = M(MgSO4•xH2O);

M(xH2O) = M(MgSO4•xH2O) - M(MgSO4) = 246.55 g/mol - 120.366 g/mol = 126.184 g/mol;

x = M(xH2O)/M(H2O) = (126.184 g/mol) / (18.015 g/mol) = 7;

Answer: 7 

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