M(MgSO4) = 120.366 g/mol;
M(H2O) = 18.015 g/mol;
Proportion:
120.366 g (mass of 1 mole of MgSO4) — 48.82 %
Total mass of 1 mole of MgSO4•xH2O — 100 %
M(MgSO4•xH2O) = 246.55 g/mol;
M(MgSO4) + M(xH2O) = M(MgSO4•xH2O);
M(xH2O) = M(MgSO4•xH2O) - M(MgSO4) = 246.55 g/mol - 120.366 g/mol = 126.184 g/mol;
x = M(xH2O)/M(H2O) = (126.184 g/mol) / (18.015 g/mol) = 7;
Answer: 7
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