Answer to Question #114781 in General Chemistry for Janene Kabiira

Question

Pentane (C5H12) burns with oxygen to produce carbon dioxide and water. What mass of
C5H12 is required to produce 450.0 g of CO2? (3 marks)
C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(l)

Answer 1

M(C₅H₁₂) = 72.15 g/mol;

M(CO₂) = 44.01 g/mol;

n=m/M;

n(CO₂) = 450 g/(44.01 g/mol) = 10.22 moles;

Proportion according to the reaction:

1 mole (pentane) — 5 moles (CO₂)

x moles (pentane) — 10.22 moles (CO₂)

x = 2.044 moles;

m = n×M;

m(pentane) = 2.044 moles × 72.15 g/mol = 147.47 g

Answer: 147.47 g