Question

The following reaction uses 3.42 g of nitrogen dioxide (NO2). What volume of dinitrogen tetroxide gas would be collected at 227 ̊C and 10.0 atm?
2 NO2 → N2O4

Answer 1

$2NO_2 \rightarrow N_2O_4$

Convert g of $NO_2$ to moles

$3.42 g (\frac{1 mol}{46.01g})=0.0743 mol$

Covert moles of $NO_2$ to moles of $N_2O_4$

$0.0743 mol NO_2(\frac{1 mole N_2O_4}{2 moles NO_2})=0.0372 mol N_2O_4$

use Ideal Gas Law to find the volume of $N_2O_4$

$PV=nRT$

$V=\frac{nRT}{P}=\frac{0.0372\times0.082 \times (273+227)}{10.0}=0.153 L$