Solution.
Vi=2.0L;V_i=2.0L;Vi=2.0L;
pi=740mmHg;p_i=740mmHg;pi=740mmHg;
pf=760mmHg;p_f=760mmHg;pf=760mmHg;
Vf−?;V_f - ?;Vf−?;
pV=const;pV=const;pV=const;
piVi=pfVf; ⟹ Vf=piVipf;p_iV_i=p_fV_f;\implies V_f=\dfrac{p_iV_i}{p_f};piVi=pfVf;⟹Vf=pfpiVi;
Vf=740mmHg⋅2.0L760mmHg=1.95L;V_f=\dfrac{740mmHg\sdot2.0L}{760mmHg}=1.95L;Vf=760mmHg740mmHg⋅2.0L=1.95L;
Answer: Vf=1.95L.V_f=1.95L.Vf=1.95L.
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