C1(NaOH) = 19 M;
C2(NaOH) = 0.25 M;
V1 = 2 ml;
V2 = unknown.
Proportion 1:
19 moles — 1000 ml
x moles — 2 ml
x = 0.038 moles in 2 ml of 19 M NaOH;
Proportion 2:
0.25 moles — 1000 (ml)
0.038 moles — y (ml)
y = 152 ml (final volume of the solution);
V(H2O) = 152 ml — 2 ml = 150 ml;
Answer: V(H2O) = 150 ml; V(final) = 152 ml
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