Question

You have a 46 g sample of watr at a temp of -58 C.
How many Joules of energy are neccessary to
a. Heat the ice to 0C?
b. Melt the ice ?
c. Heat the water from 0 C to 100C?
d.Boil the water?
e. heat the steam from 100 C to 114 C?

Answer 1

a) $H=mc\Delta T=46\times2.1\times58=5602.8 J$

b) A total of 334 J of energy are required to melt 1 g of ice at 0°C, which is called the latent heat of melting

Here H=334 x 46=15364 J

c) $H=mc\Delta T=46\times4.2\times100=19320 J$

d)The latent heat of vaporization for water is 22.6 x 10² J/g

H=2260 x 46 = 103960 J