The ionic product of water is defined as:
Kw=[H3O+][OH−]=10−14K_w = [H_3O^+][OH^-] = 10^{-14}Kw=[H3O+][OH−]=10−14 .
Therefore, the concentration of hydroxide ions is:
[OH−]=Kw[H3O+]=10−141.5⋅10−6=6.7⋅10−9[OH^-] =\frac{K_w}{[H_3O^+]} =\frac{10^{-14}}{1.5\cdot10^{-6}}=6.7\cdot10^{-9}[OH−]=[H3O+]Kw=1.5⋅10−610−14=6.7⋅10−9 M.
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