Answer to Question #114493 in General Chemistry for Jazmine Solis

Question #114493

Calculate the molarity of 0.060 moles of NaHCO3 in 1500. mL of solution

Expert's answer

C(NaHCO₃) = n(NaHCO₃)/V(NaHCO₃) = 0.060/1.5 = 0.04 M

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