"2LiOH(s) + CO_2(g) \u2192 Li_2CO_3(s) + H_2O(l)"
we can see that ratio of stochiometric coefficients ratio of LiOH and carbon dioxide is 2:1
which means that for every two moles of LiOH , one mole of carbon dioxide is consumed
moles of LiOH "=\\frac{1000}{24}=41.67"
moles of carbon dioxide consumed will be half of LiOH=41.67/2=20.83
mass of CO2 consumed =20.83"\\times"44 =916.52 grams
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