Answer to Question #114284 in General Chemistry for Daniel

General Chemistry

Question #114284

How many liters of Cl2 gas are occupied by 710g of it at STP?

Expert's answer

T = 273.15 K

P = 101.325*10³ Pa

m(Cl₂) = 710g

R = 8.314 J/K*mol

PV = m*R*T/M

V = m*R*T/M*P = (710g*8.314 J/K*mol*273.15 K)/(71g/mol*101.325*10³ Pa) = 0.224 m³= 224 L

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