Answer to Question #114241 in General Chemistry for Daniel

Question #114241

When sufficient copper and nitric acid reacted to make 645 cm3 of NO (g) @SATP, how many grams of water were produced?

Expert's answer

4HNO₃ + 3Cu = 3CuNO₃ + NO +2H₂O

V=n x 22.4.

n=V/22.4 = 645/22.4 x 1000 = 0,0287946429 moles.

m_H2O= 18 x 2 x 0,0287946429= 1,03660714 g of water.

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