Question #114028
What would be the pH of a 0.0123 M solution of HCl
1
Expert's answer
2020-05-05T04:52:05-0400
[H+]=0.0123M[H^+] = 0.0123M

pH=−log[H+]pH = -log[H^+]

pH=−log(0.0123)=1.91pH = -log(0.0123) = 1.91


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