Molar mass of Li3NLi_3NLi3N is 35 gms.
Thus 87.2grams=87.2/35moles87.2 grams =87.2/35 moles87.2grams=87.2/35moles .
1 mole Li3NLi_3NLi3N reacts with 3 moles of Li
Thus Lithium required is 87.2∗3/35moles87.2*3/35 moles87.2∗3/35moles
Atomic mass of Li is 7 gms.
Thus, mass of lithium required is
87.2∗3∗7/35=52.32gms.87.2*3*7/35=52.32 gms.87.2∗3∗7/35=52.32gms.
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