Answer to Question #114008 in General Chemistry for Coast

Question

In a laboratory experiment,
Cu combines with oxygen to
produces 2 oxides X and Y. After
the experiment, it was determined
that 3.07g of X yielded 2.73g
copper and 2.90g of Y yielded
2.32g of cooper.
Mass of the oxide = (
Mass of copper = (
Mass of oxygen =
Number of moles of oxygen =
/16
)moles (4 d.p)
Number of moles of copper=
/63.5
moles
Mole ratio of Cu:0 =
moles (4 d.p)
Simple whole number ratio Cu:0 =
Chemical formula of X = Cu
To determine the chemical formula of Y
Mass of the oxide = (
g(2 d.p)
Mass of copper =
(2 d.p)
Mass of oxygen=
Number of moles of oxygen
/16
moles (4 d.p)
Number of moles of copper
/63.5
moles (4 d.p)
Mole ratio of Cu:0 = (
)(4 d.p)
Simple whole number ratio Cu:0 =
Chemical formula of X = Cu
The law of chemical combination illustrated by the
result above is the Law of

Answer 1

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