Solution.
4mol4mol4mol xmolx molxmol
O2+2Mg→2MgO;O_2+2Mg\to 2MgO;O2+2Mg→2MgO;
222 222
We make the proportion: 4mol2=xmol2;\dfrac{4mol}{2}=\dfrac{xmol}{2};24mol=2xmol;
x=4mol⋅22=4mol;x=\dfrac{4mol\sdot2}{2}=4mol;x=24mol⋅2=4mol;
ν(MgO)=4mol\nu(MgO)=4molν(MgO)=4mol ;
Answer: ν(MgO)=4mol.\nu(MgO)=4mol.ν(MgO)=4mol.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments