Solution (1):
Equation: 2AgNO3(aq) + CaBr2(aq) → Ca(NO3)2(aq) + 2AgBr(s)
Ionic Equation:
2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Br-(aq) → Ca2+(aq) + 2NO3-(aq) + 2AgBr(s)
Net Ionic Equation: 2Ag+(aq) + 2Br-(aq) → 2AgBr(s)
Or: Ag+(aq) + Br-(aq) → AgBr(s)
Answer (1): Ca(NO3)2(aq) + AgBr(s).
Solution (2):
Molarity of Ba(OH)2 = Moles of Ba(OH)2 / Volume of solution
Volume of solution = Moles / Molarity
Volume of solution = (2 mol) / (0.25 M) = 8 L.
The actual volume of water will be somewhat less than that since the 2 moles of Ba(OH)2 will occupy some volume.
However, suppose that:
Volume of solution = m(H2O) = 8 L.
Answer (2): 8 Liters of water.
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