Answer to Question #113511 in General Chemistry for Jonathan Jacques Pluviose

Question

If there are 0.0345 mols of HI in 47 mL of solution, what is its concentration? Also, what
is the pH?

Answer 1

C = n/V

C = 0.0345/0.047 = 0.734 M

HI is a strong acid and dissociates completely.

HI -> H⁺ + I^-

[H⁺] = 0.734 M

pH = -Log[H⁺] = -Log(0.734) = 0.134