Answer to Question #113511 in General Chemistry for Jonathan Jacques Pluviose

Question #113511

If there are 0.0345 mols of HI in 47 mL of solution, what is its concentration? Also, what
is the pH?

Expert's answer

C = n/V

C = 0.0345/0.047 = 0.734 M

HI is a strong acid and dissociates completely.

HI -> H⁺ + I^-

[H⁺] = 0.734 M

pH = -Log[H⁺] = -Log(0.734) = 0.134

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