In CaCl2 the chemical formula tells us that there are two moles of Cl- in every mole of compound.
In our case there are 0.015 moles of CaCl2.
M(CaCl2)=110.98 g/mol
m = n×M
m(CaCl2) = 0.015 mol × 110.98 g/mol = 1.6647 g
Answer: 1.66 g.
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