Question

Calculate the mass of silver trioxonitrate(v) in 500cm'3 of 0.01 M Ag NO in grammes

Answer 1

For the beginning we should calculate the amount of substance of AgNO₃:

$\nu = C•V$ = 0.01(M) • 0.5(L) = 0.005 mol

Then, the mass will be calculated by this formula:

$m = \nu•M$ = 0.005(mol) • 169.87(g/mol) = 0.85 g

Answer: m(AgNO₃) = 0.85 g