Answer in General Chemistry for gracie #113288

Question #113288

When a sample of C2H5OH was combusted, the volume of CO2(g) produced was 18.0L when measured at 21.7°C and 1.03atm . Determine the number of moles of CO2(g) that was produced.

Expert's answer

Assume ideal gas and use the law:

p*V = n*R*T

p = 1.03*101.325 = 104.36475 kPa

V = 18.0 L

R = 8.314 J/(K*mole)

T = 21.7+273.15 = 294.85 K

n = 18*104.36475/(8.314*300.25) = 0.77 mole

Number of CO2(g) moles is 0.77

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Comments

Abdullah

30.10.20, 04:36

This is wrong. He/she got the wrong temp. 21.7 +273.5 is 294.85, NOT 300.25. Otherwise, everything else is fine :)