Question #113288
When a sample of C2H5OH was combusted, the volume of CO2(g) produced was 18.0L when measured at 21.7°C and 1.03atm . Determine the number of moles of CO2(g) that was produced.
Expert's answer
Assume ideal gas and use the law:
p*V = n*R*T
p = 1.03*101.325 = 104.36475 kPa
V = 18.0 L
R = 8.314 J/(K*mole)
T = 21.7+273.15 = 294.85 K
n = 18*104.36475/(8.314*300.25) = 0.77 mole
Number of CO2(g) moles is 0.77
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#332078 on Oct 2022
#332078 on Oct 2022
Comments
This is wrong. He/she got the wrong temp. 21.7 +273.5 is 294.85, NOT 300.25. Otherwise, everything else is fine :)