Question

At what temperature will 2.40 moles of chlorine gas exert a pressure of 2.70 atm at a volume of 0.750 L?

Answer 1

Use the ideal gas law:

PV = nRT

Based on this (R = 0.0821 L·atm/mol·K):

T = PV/nR = (2.70*0.750)/(2.40*0.0821) = 10.28 K

So. at 10.28 K set quantity chlorine gas exert a pressure of 2.70 atm at a volume of 0.750 L