Answer to Question #113265 in General Chemistry for Ideal gas law

Question

354.5 g of chlorine gas (MW = 70.9 g/mol) is held in a vessel with a fixed volume of 70.0 L. What is the pressure of the gad in the atmosphere of it's temperature is 30.0 °C

Answer 1

Using the Clapeyron-Mendeleev equation: $PV=nRT$ , P - gas pressure (Pa) , V - gas volume (m³), n - chemical amount of gas (mol), T - temperature of gas (K), R - Gas constant (8,314 J/(mol*K)).

$n=m/M$ , n - chemical amount of substance (mol); m - mass of substance (g); M - molar mass of substance (g/mol). 

n=354,5g/70,9g/mol=5mol

Express P: $nRT/V=P$

T=30.0oC=303K

V=70,0l=0,070m³

P=5mol*(8,314 J/(mol*K)*303K/0,070m³=179938,714Pa

P=179938,714Pa=1,776atm

Answer:1,776atm