Answer to Question #113204 in General Chemistry for Mohammed Al-fatlawi

Question

How many atoms of nitrogen are in 10.0g of N2O5 ?

Answer 1

Solution:

Moles of N₂O₅ = Mass of N₂O₅ / Molar mass of N₂O₅

Molar mass of N₂O₅ is 108.0104 g/mol.

Then,

Moles of N₂O₅ = (10.0 g) / (108.0104 g/mol) = 0.09258 mol

N₂O₅ --> 2N

Moles of nitrogen (N) = 2 × Moles of N₂O₅ = (2 × 0.09258 mol) = 0.18516 mol

As 1 mole of any substance contains 6.022×10²³ particles, 0.18516 mol of nitrogen contains:

Number of nitrogen atoms = (0.18516 mol) × (6.022×10²³) = 1.115×10²³ atoms = 1.1×10²³ atomf of N.

Answer: 1.1×10²³ atoms of nitrogen in 10.0g of N₂O₅.