Answer:
The balanced reaction equation is:
2SO2 + O2 + 2H2O "\\rightarrow" 2H2SO4
As you can see, the number of the moles of SO2 reacted is equal to the number of the moles of H2SO4 produced:
"n(SO_2) = n(H_2SO_4)"
The molar mass "M" of SO2 is 64.06 g/mol. Let's calculate the number of the moles of SO2:
"n(SO_2) = \\frac{m}{M} = \\frac{9.82}{64.06} = 0.153" mol
The molar mass "M" of H2SO4 is 98.08 g/mol. Then, the mass of H2SO4 produced is:
"m(H_2SO_4) = n\u00b7M = 0.153\u00b798.08 =15.04" g
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