if we consider the first degree of dissociation
H2SO4 = H+ + HSO4–
C(H+) = С(H2SO4) = 2 M
рН = – lg(C(H+)) = –lg 2 = -0.3
if we consider the second degree of dissociation
H2SO4 = 2H+ + SO42-
2C(H+) = С(H2SO4) = 4 M
pH = – lg(2C(H+)) = -lg 4 = -0.6
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