Question #112957

Calculate the pH of a 2 M solution of H2SO4.

Expert's answer


if we consider the first degree of dissociation

H2SO4 = H+ + HSO4

C(H+) = С(H2SO4) = 2 M

рН = – lg(C(H+)) = –lg 2 = -0.3


if we consider the second degree of dissociation

H2SO4 = 2H+ + SO42-

2C(H+) = С(H2SO4) = 4 M

pH = – lg(2C(H+)) = -lg 4 = -0.6


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