Answer to Question #112955 in General Chemistry for Nicolas
Calculate the pH of a 0.0035 M solution of HNO3.
1
2020-05-01T14:42:10-0400
[OH-] = 0.0035 M
pH = 14 - pOH
pOH = -Log[OH-] = 2.456
pH = 14 - 2.456 = 11.544
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