first of all lets calculate the concentration of OH- ions which is 5×10−35\times10^{-3}5×10−3
and as we know that [H+][OH−]=10−14[H^+][OH^-]=10^{-14}[H+][OH−]=10−14
[H+]=10−14/(5×10−3)=2×10−12[H^+]=10^{-14}/(5\times10^{-3})=2\times10^{-12}[H+]=10−14/(5×10−3)=2×10−12
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