Question

Calculate the OH-1 concentration in 0.0325 M HCl.

Answer 1

pH+pOH=14

pH=−log[H₃O⁺]

pOH=−log[OH⁻]

HCl is completely ionized in water because HCl is a strong acid so the H₃O⁺ concentration will also be 0.0325 mol/L.

pH=−log[0.0325]

pH=1.48

1.48 + pOH = 14

pOH= 12.52

12.52 = −log[OH⁻]

10^−(12.52) = [OH⁻]

[OH⁻] = 10^−(12.52) = 3.02×10⁻¹³ mol/L

Answer: 3.02×10⁻¹³ mol/L