"3H_2 + N_2 \\to 2NH_3"
As per stochiometry
"2" moles of "NH_3" require "3" moles of "H_2."
"3.2" moles of "NH_3" will produce "\\frac{3}{2}\\times 3.2=4.8" moles of "H_2" .
Molar mass of "H_2" is "1\\ g."
Mass of "H_2" required"=1\\times 4.8=4.8\\ g."
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