Question

A balloon has an initial volume of 10 liter, the pressure is 10 atm, and the temperature is 30k. If the temperature changes to 40k and the pressure changes to 2 atm, what is the new volume?

Answer 1

Given : $V_i=10L;P_i=10atm;T_i=30K; T_f=40K;P_f=2atm$

To find : $V_f=?$

Solution : Ideal gas law : $PV/nRT=constant \implies P_iV_i/T_i=P_fV_f/T_f$

$\implies V_f=P_iV_iT_f/P_fT_i=10*10*40/(2*30)=400/6$

$=66.667 L$ ---(Answer)