The balanced equation for considered reaction can be written as follows
"3NO_2 + H_2O \\rightarrow 2HNO_3 + NO"
"\\frac{\\nu (NO_2)}{n(NO_2)} = \\frac{V(NO)}{V_M \\cdot n(NO)}"
where "\\nu" - amount, mol; "V" - volume, L; "V_M" - molar volume of a gas, "V_M=22.4 \\; L\/mol" ; "n" - number of molecules in the balanced equation.
"V(NO)=\\frac{\\nu (NO_2) \\cdot V_M \\cdot n(NO)}{n(NO_2)}"
"V(NO)=\\frac{7.0 \\cdot 22.4 \\cdot 1}{3} \\approx 52.3 \\; L"
Answer: 52.3 L.
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