For calculations, we take a sample of the starting substance weighing 100 g:
"m(H20)=\\frac{\\omega(H20)\\times100}{100}=36.41 g"
m( MnCl2)=100-36.41=63.59
find the amount of substance:
"n(H20)=\\frac{m}{M}=\\frac{36.41}{18}=2.023"
"n(Mncl2)=\\frac{m}{M}=\\frac{63.59}{125.8440}=0.505"
x:y=0.505:2.023=1:4
MnCl2*4H20
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