Answer to Question #112046 in General Chemistry for Anastasia

Question

2.0mol of (NH4)3PO4
calculate the grams of phosphate (PO4) ions

Answer 1

$m=nM$ , n - chemical amount of substance(mol); m - mass of substance(g); M - molar mass of substance(g/mol).

2,0 mol of (NH₄)₃PO₄ contains 2,0 mol PO₄^3-

M(PO₄^3-)=31,0g/mol+16,0g/mol*4=95,0g/mol

m(PO₄^3-)=95.0g/mol*2,0mol=190,0g

Answer:190,0g.