Question

How hot (in °C) will a 1.40 L balloon have to get to expand to a volume of 2.5 L? The initial temperature of the balloon is 32 °C. Use Charles’ Law.

Answer 1

Charles’ Law:

$${V_1 \over T_1} = {V_2 \over T_2}$$

Then:

$$T_2 = {T_1V_2 \over V_1}$$

$$T_2 = {32 ^0C*2.5L \over 1.4L} = 57^0C$$

Answer: 57 ⁰C