Answer to Question #111740 in General Chemistry for Vanetta Green

Question

A solution contains 35 mL of 1.50M CuSO4. What is the molarity when the new volume is 100L?

Answer 1

Formula:

C = n/V, where

C - concentration, mol/l;

n - amount of substance, mol;

V - volume of the solution, l.

C₁ = n_{CuSO4 /} V_solution

Herefrom, n_CuSO4 = C₁ • V₁ = 1,5 mol/l • 0,0035 l = 0,00525 mol

C₂ = n/V₂ = 0,00525 mol / 100 l = 5,25•10^-5 mol/l.

Answer: 5,25•10^-5 mol/L.

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