Answer to Question #111714 in General Chemistry for Daniel

Question

How many moles of atoms are in 15.0 g of ZN3(PO4)2?

Answer 1

Solution.

m(Zn₃(PO₄)₂) = 15.0 g;

M(Zn₃(PO₄)₂) = 385 g/mol;

$\nu$ = m/M; $\nu$ =15.0 g/ (385 g/mol ) = 0.03896 mol;

Answer: $\nu$ = 0.03896 mol.