Answer to Question #111714 in General Chemistry for Daniel

General Chemistry

Question #111714

How many moles of atoms are in 15.0 g of ZN3(PO4)2?

Expert's answer

Solution.

m(Zn₃(PO₄)₂)= 15.0 g;

M(Zn₃(PO₄)₂) = 385 g/mol;

"\\nu" = m/M; "\\nu" =15.0 g/ (385 g/mol ) = 0.03896 mol;

Answer: "\\nu" = 0.03896 mol.

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