The molarity of the solution can be calculated using the following formula:
M = n / V = m / (Mr × V)
where M - molarity, n - number of moles, m - mass, Mr - molecular weight, V - volume.
As Mr(Al2(SO4)3) = 342 g/mol and V = 238.7 mL = 0.2387 L
M = 29.6 g / (342 g/mol × 0.2387 L) = 0.363 mol/L = 0.363 M
Answer: 0.363 M
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