Answer to Question #111410 in General Chemistry for Radiah Jamil

Question

In a titration, 21.34 mL of 0.00343 M
Ba(OH)2 neutralized 10.9 mL of HCl solution.
What is the molarity of the HCl solution?
Answer in units of M.

Answer 1

Solution.

V(Ba(OH)₂) = 21.34 mL;

M(Ba(OH)₂ ) =  0.00343 M ;

V(HCl) = 10.9 mL;

M(HCl) - ?;

Because the reaction is a 1:1 rxn ratio, it is useful to apply

(Molarity x Volume)Acid = (Molarity x Volume)Base;

M(HCl)xV( HCl) =M(Ba(OH)₂)x V(Ba(OH)₂);⟹

M(HCl) =(M(Ba(OH)₂)x V(Ba(OH)₂)) /V(HCl);

M(HCl) = (0.00343 M x 21.34 mL)/10.9 mL = 0.00672 M;

Answer: M(HCl) = 0.00672 M.