Question #111410
In a titration, 21.34 mL of 0.00343 M
Ba(OH)2 neutralized 10.9 mL of HCl solution.
What is the molarity of the HCl solution?
Answer in units of M.
Ba(OH)2 neutralized 10.9 mL of HCl solution.
What is the molarity of the HCl solution?
Answer in units of M.
Expert's answer
Solution.
V(Ba(OH)2) = 21.34 mL;
M(Ba(OH)2 ) = 0.00343 M ;
V(HCl) = 10.9 mL;
M(HCl) - ?;
Because the reaction is a 1:1 rxn ratio, it is useful to apply
(Molarity x Volume)Acid = (Molarity x Volume)Base;
M(HCl)xV( HCl) =M(Ba(OH)2)x V(Ba(OH)2);⟹
M(HCl) =(M(Ba(OH)2)x V(Ba(OH)2)) /V(HCl);
M(HCl) = (0.00343 M x 21.34 mL)/10.9 mL = 0.00672 M;
Answer: M(HCl) = 0.00672 M.
