Answer to Question #111409 in General Chemistry for Radiah Jamil

Question

A 22.9 mL sample of a solution of RbOH is
neutralized by 18.82 mL of a 1.649 M solution
of HBr. What is the molarity of the RbOH
solution?
Answer in units of M.

Answer 1

Solution.

V(RbOH) =  22.9 mL;

V( HBr) = 18.82 mL;

M(HBr) =1.649 M;

M(RbOH) - ?;

Because the reaction is a 1:1 rxn ratio, it is useful to apply

(Molarity x Volume)Acid = (Molarity x Volume)Base;

M(HBr)xV( HBr) =M(RbOH)x V(RbOH);$\implies$

M(RbOH) = (M(HBr)xV( HBr))/V(RbOH);

M(RbOH) =(1.649 Mx18.82 mL)/22.9 mL = 1.355M;

Answer: M(RbOH) =1.355M.