Answer to Question #111393 in General Chemistry for ella

Question

in the dissociation of (NH4)2SO4(aq), 0.980 mil of solute was added to 1.85 L of water. what is the concentration of surface ions in the resulting solution

Answer 1

Solution.

$\nu$ (solute) = 0.980 mol;

V( solution) = 1.85 L;

concentration (molarity)  = moles of solute /liter of solution;

concentration (molarity) = 0.980 mol/1.85 L = 0.53 mol/L;

Answer: concentration = 0.53 mol/L;